PENJUMLAHAN DAN PENGURANGAN BILANGAN BULAT
1. Tanda "BEDA" pikir "KURANG"
2. Tanda "SAMA" pikir "JUMLAH"
3. Tanda "BERURUTAN KALIKAN TANDA"
Perkalian Tanda
PENJUMLAHAN BILANGAN BULAT
- $ -5 + 3 = ...$
- $-4 + 2 = ...$
- $-6 + 5 = ... $
- $-8 + 6 = ...$
- $-9 + 9 = ...$
- $-8 + 5 = ...$
- $-10 + 6 = ...$
- $-10 + 4 = ...$
- $-15 + 10 = ...$
- $-8 + 7 = ...$
- $ -3 + 5 = ...$
- $-2+4 = ...$
- $-5 + 6 = ...$
- $-6 + 8 = ...$
- $-5 + 8 = ...$
- $-10 +15 = ...$
- $-12 + 17 = ...$
- $ -8 + 10 = ...$
- $-9 + 10 =...$
- $ -20 + 20 = ...$
PENGURANGAN BILANGAN BULAT
- $-2 - 3 = ...$
- $-1 - 5 = ...$
- $-3 - 4 = ...$
- $-5 - 4 = ...$
- $-5 - 5 = ...$
- $2 - 3 = ...$
- $5 - 9 = ...$
- $4 - 6 = ...$
- $8 - 3 = ...$
- $5 - 3 = ...$
- $-2 - \left ( -3 \right )= ...$
- $-5 - \left ( -6 \right )= ...$
- $-5 - \left ( -5 \right )= ...$
- $-7 - \left ( -4 \right )= ...$
- $-10 - \left ( -6 \right )= ...$
- $-2 - \left ( -8 \right )= ...$
- $-2 + \left ( -3 \right )= ...$
- $-9 + \left ( -6 \right )= ...$
- $-6 + \left ( -6 \right )= ...$
- $-5 + \left ( -6 \right )= ...$
OPERASI HITUNG CAMPURAN PENJUMLAHAN DAN PENGURANGAN BILANGAN BULAT
- $2 + 4 - 3 = ...$
- $3 +\left ( -4 \right )-\left ( -3 \right )=...$
- $-3 - 4 +\left ( -5 \right )= ...$
- $-5 + 4 - \left ( -3 \right )= ...$
- $6 - \left ( -3 \right )+\left ( -5 \right )= ...$
- $-5 + 4 - 3 = ...$
- $-2 +\left ( -2 \right )+\left ( -5 \right )=...$
- $5 - 6 +\left ( -2 \right )= ...$
- $7 - \left ( -2 \right )+\left ( -4 \right )= ...$
- $-6 + \left ( -4 \right )-\left ( -10 \right )= ...$
- $8 - \left ( -2 \right )+\left ( -4 \right )= ...$
- $-7 - \left ( -5 \right )+\left ( -4 \right )= ...$
- $8 + \left ( -2 \right )-\left ( -4 \right )= ...$
- $9 - \left ( -1 \right )+\left ( -6 \right )= ...$
- $-6 + 9 - 3 = ...$
- $-10 + 6 - 4 = ...$
- $4 +\left ( -4 \right )-\left ( -2 \right )=...$
- $-9 +\left ( -2 \right )-\left ( -5 \right )=...$
- $3 +\left ( -6 \right )+\left ( -4 \right )=...$
- $-3 +\left ( -4 \right )-\left ( -3 \right )=...$
ALJABAR DASAR
Bentuk-Bentuk Aljabar
biasanya suatu permasalahan ditulis terlebih dahulu dalam bentuk aljabar agar penyelesaiannya lebih mudah. Bentuk aljabar terdiri dari konstanta, variabel, dan koefisien yang dihubungkan melalui operasi penjumlahan, pengurangan, perkalian, pembagian, perpangkatan, dan pengakaran.
PENJUMLAHAN DAN PENGURANGAN BENTUK ALJABAR
Syarat : Suku harus "SEJENIS"
contoh Suku - suku sejenis
- 2 dan 3
- 2m dan 3m
- -3a dan 5a
- x dan 7x
- $2x^{2} dan -5x^{2}$
- -3ab dan -6ab
- dll
LATIHAN SOAL
sederhanakan bentuk - bentuk aljabar berikut!
- $9a + 14ab-17a$
- $7a^{3} -8a^{2}-16a^{3}+11a^{2}+9$
- $-7x + 2y - 8x + 4y + 5$
- $2a + 4b - 8 + a - 3b + 7$
- $9a + 7b - 4 -4a - 9b + 13$
- $p + 8p + 6 - 5p - 3p - 5$
- $3x + 15y + 10 - 2x - 10y -19$
- $4x - 5y + 10- 14x - 7y - 10$
- $3x + 17y + 8 + 13x - 20y -12$
- $x^{3}+6x^{2}-x+\left ( -5x \right )^{3}-3x^{2}+8x$
- $4a+10b-9a+12ab$
- $5p-6pq-7p^{2}+16pq+8p$
- $7m^{2}+8m+6-9m^{2}-2m+10$
- $3x^{2}y-2xy+7x^{2}y^{2}-4xy^{2}-8xy$
- $8\left ( 3x+4 \right )-5\left ( 4x-6 \right )$
- $5\left ( 4x-3y \right )+3\left ( 5x+2y \right )$
- $4x-11y-9z-\left ( -8x+10y-9z \right )$
- $11p^{2}-17p+24-\left ( 2p^{2}+15p-18 \right )$
- $6a-5b-2c+\left ( -8a+6b+9c \right )$
- $-5\left ( 4y^{2}-2y+8 \right )-4\left ( 7y^{2}+6y-5 \right )$
Diketahui $A = 3x + 5y$ dan $B = 4x - 2y$. Tentukan nilai - nilai berikut dinyatakan dalam x dan y
- $A+B$
- $A-B$
- $2A+B$
- $A-\frac{1}{2}B$
- $4A+3B$
- $3A-1\frac{1}{2}B$
PERKALIAN BENTUK ALJABAR
Tentukan hasil perkalian bentuk-bentuk aljabar berikut!
- $7\times a\times 4b\times 5a$
- $ -6\times \left ( -3q \right )\times 4pq\times \left ( -p \right )$
- $3m\times 2kn\times \left ( -4mn \right )\times 6km$
- $8xz\times 3y^{2}z\times \left ( -4x^{2} y\right )$
- $2p^{2}\times \left ( -5qr \right )\times 3pq^{2}\times \left ( -pr^{2} \right )$
- $-6mx^{2}\times 2xy^{2}\times \left ( -4my \right )\times \left ( -5m^{2}xy^{2} \right )$
- $a\left ( 3a+8b \right )$
- $2a\left ( 7a^{2}+4b \right )$
- $-5p^{2}\left ( 6p-3q \right )$
- $3q\left ( 6p^{2}+5pq-4q^{2} \right )$
- $-2mn\left ( 3m^{2}-4mn-7n^{2} \right )$
- $5m^{2}\left ( 2m^{2}+8m^{2}n-5mn^{2} \right )$
- $\left ( x+4 \right )\left ( x+15 \right )$
- $\left ( 2x-5 \right )\left ( 2x+3 \right )$
- $\left ( 4x+3 \right )\left ( 5x-2 \right )$
- $\left ( 8-5x \right )\left ( 9-5x \right )$
- $\left ( 10-3p \right )\left ( 7+3p \right )$
- $\left ( 15+6p \right )\left ( 8-4p \right )$
- $\left ( 8p+3q \right )\left ( 6p+7q \right )$
- $\left ( 2x-3 \right )\left ( 4x^{2}+6x+9 \right )$
- $\left ( 2p+q \right )\left ( p^{2}+pq+q^{2} \right )$
PEMBAGIAN BENTUK ALJABAR
- $18a^{4}b\div 3a^{3}b$
- $36a^{8}b^{3}\div 9a^{5}b^{2}$
- $28p^{5}q^{9}r^{3}\div \left ( -4p^{2}q^{7} \right )$
- $-32p^{7}q^{8}r^{4}\div 8pq^{6}r$
- $15x^{6}\div \left ( 24x^{5}\div \left ( -8x^{3} \right ) \right )$
- $56x^{7}y^{6}\div \left ( -4x^{4}y^{5}\div 2x^{2}y^{4} \right )$
- $m^{6}n^{9}\div \left ( m^{4}n^{3}\times mn^{4} \right )$
PERSAMAAN LINEAR SATU VARIABEL
Tentukan penyelesaian dari persamaan - persamaan berikut!
- $x+8=15$
- $x+5=-12$
- $x+16 = 7$
- $x-9=10$
- $x-14=18$
- $a-3=2$
- $b+6=9$
- $x-4=-3$
- $y+7=4$
- $x+9=4$
- $y-3=-10$
- $2p+1=7$
- $5q-4=-19$
- $8m+12=5m$
- $6n+17=17$
- $4p-10=9p$
- $3q+2=2q-1$
- $3q+2=2q-1$
- $7x-5=5x+9$
- $4y+6=6y-7$
- $9p+9=8p+4$
- $5p+7=6p-14$
- $7p-14=6p-8$
- $14x-10+4x=17x+7$
- $24x+18-4x=21x-12$
- $3\left ( 2x+7 \right )=5\left ( x-4 \right )$
- $2\left ( 5x-6 \right )=3\left ( 3x-7 \right )+2x$
- $2x=14$
- $4x=-12$
- $-6y=-3$
- $-\frac{3}{4}y=-\frac{3}{8}$
- $-2a=-\frac{1}{3}$
- $\frac{1}{4}a=\frac{2}{3}$
- $-\frac{p}{3}=-1$
- $-\frac{p}{3}=-2$
- $4a+5=37$
- $3a-4=11$
- $8x-8=-24$
- $6x+7=-29$
- $3p=15+6p$
- $5p-8=7p+12$
- $9-2y=4y-6$
- $4\left ( y-3 \right )=11y+7$
- $5\left ( y+2 \right )=9y-15$
- $2\left ( q+3 \right )+\left ( 3q-4 \right )=9$
- $3\left ( q-1 \right )+4\left ( q-5 \right )=-5$
- $4\left ( x-3 \right )-2\left ( x-3 \right )=8$
- $4x+3\left ( x-2 \right )-\left ( 5-4x \right )=0$
- $6p-7\left ( 2p-3 \right )=3\left ( 4p-3 \right )$
- $5\left ( 2p+3 \right )-12p+9=3\left ( 3p-5 \right )$
- $3\left ( 2x-3 \right )-2\left ( x+1 \right )=x-3$
- $8y-5\left ( 2y-3 \right )=4\left ( y-3 \right )+18$
- $5\left ( 2y+4 \right )-\left ( 10y-16 \right )=6-4y$
- $6x-7\left ( 2x-3 \right )=3\left ( 4x-3 \right )$
- $\frac{1}{2}x+3=9$
- $\frac{1}{3}x-5=10$
- $\frac{1}{4}x+\frac{1}{2}=7$
- $\frac{3}{4}x-\frac{1}{5}x=2$
- $\frac{y}{2}=\frac{y}{7}-10$
- $\frac{1}{2}\left ( 4x-5 \right )=\frac{1}{4}x+3\frac{1}{2}$
- $\frac{1}{6}\left ( 3x+1 \right )+\frac{1}{3}\left ( x-2 \right )=1\frac{1}{6}$
- $\frac{1}{2}\left ( 2x-5 \right )+\frac{2}{3}\left ( 6-x \right )=\frac{5}{6}x$
- $\frac{y+4}{4}-\frac{3y-9}{7}=\frac{1}{2}$
- $\frac{4-y}{2}-\frac{y+1}{3}=\frac{1}{4}$
- $\frac{y+3}{4}+\frac{1-2y}{5}=\frac{y-5}{10}$
- $\frac{4y+2}{3}+\frac{2y+1}{2}=\frac{6y+3}{4}$
- $\frac{2y-3}{4}-\frac{3y+4}{2}=\frac{4y+2}{8}$
- $\left ( x+6 \right )\left ( x+3 \right )=x\left ( x+8 \right )$
- $\left ( x+8 \right )\left ( x-5 \right )=x\left ( x-2 \right )$
- $\left ( 6x-5 \right )\left ( x+3 \right )=2x\left ( 3x+4 \right )$
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